Difference between revisions of "Open Problems:65"

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A recent result in graph sketching {{cite|AhnGM-12}} can be rephrased in terms of a simultaneous message communication protocol with public coins. Specifically, suppose that $n$ players are each given a row of the adjacency matrix of some graph. The players simultaneously send a message to a central player who must then determine whether the graph is connected. Existing work shows that this is possible with $O(\log^3 n)$ bit messages from each player. Are $O(\log^2 n)$ or $O(\log n)$ bits sufficient? Also, is there a non-trivial lower bound if the players must use private coins?
 
A recent result in graph sketching {{cite|AhnGM-12}} can be rephrased in terms of a simultaneous message communication protocol with public coins. Specifically, suppose that $n$ players are each given a row of the adjacency matrix of some graph. The players simultaneously send a message to a central player who must then determine whether the graph is connected. Existing work shows that this is possible with $O(\log^3 n)$ bit messages from each player. Are $O(\log^2 n)$ or $O(\log n)$ bits sufficient? Also, is there a non-trivial lower bound if the players must use private coins?
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== Update ==
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The conjecture has been resolved by Yu {{cite|Yu-21}}.

Latest revision as of 16:28, 16 June 2022

Suggested by Andrew McGregor
Source Bertinoro 2014
Short link https://sublinear.info/65

A recent result in graph sketching [AhnGM-12] can be rephrased in terms of a simultaneous message communication protocol with public coins. Specifically, suppose that $n$ players are each given a row of the adjacency matrix of some graph. The players simultaneously send a message to a central player who must then determine whether the graph is connected. Existing work shows that this is possible with $O(\log^3 n)$ bit messages from each player. Are $O(\log^2 n)$ or $O(\log n)$ bits sufficient? Also, is there a non-trivial lower bound if the players must use private coins?

Update[edit]

The conjecture has been resolved by Yu [Yu-21].