Open Problems:69

Suggested by	Clément Canonne
Source	Baltimore 2016
Short link	https://sublinear.info/69

Let $p$ be an unknown (discrete) probability distribution over product space $[n]\times [n]$, and $\varepsilon\in(0,1]$. Suppose $p$ is $\varepsilon$-close to independent (in total variation distance), i.e. there exists a product distribution $q=q_1\times q_2$ on $[n]\times [n]$ such that $$d_{\rm TV}(p,q) = \max_{S\subseteq [n]\times[n]} \left( p(S) - q(S)\right) \leq \varepsilon.$$

Given access to independent samples drawn from $p$, the goal is to correct $p$, that is to provide access to independent samples from a distribution $\tilde{p}$ satisfying (with high probability):

1. $d_{\rm TV}(p,\tilde{p}) = O(\varepsilon)$ [the corrected distribution is faithful to the original one]
2. $\tilde{p} = p_1\times p_2$ [the corrected distribution is an actual product distribution]

with a rate as good as possible, where the rate is the number of samples from $p$ required to provide a single sample from $\tilde{p}$.

Achieving a rate of $2$ is simple: drawing $(x_1,y_1)$ and $(x_2,y_2)$ from $p$ and outputting $(x_1,y_2)$ provides sample access to $\tilde{p} = p_1\times p_2$, which can be shown to be $3\varepsilon$-close to $p$. [BatuFFKRW-01]

Question: is a rate $r < 2$ achievable? What about an amortized rate (to provide $q=o(n^2)$ samples from the same distribution $\tilde{p}$)?

What about the same question, when relaxing the second item to only ask that $p$ be improved: that is, to provide sample access to a distribution $\tilde{p}$ guaranteed to be $\frac{\varepsilon}{2}$-close to a product distribution?