Problem 95: Non-Adaptive Group Testing
Revision as of 01:42, 25 August 2019 by Krzysztof Onak (talk | contribs)
| Suggested by | Oliver Gebhard |
|---|---|
| Source | WOLA 2019 |
| Short link | https://sublinear.info/95 |
In (non-adaptive) quantitative group testing, one has a population of $n$ individuals, among which $k=n^c$ (for some constant $c\in(0,1)$) are sick. The goal is to identity the $k$ sick individuals by performing $m$ non-adaptive tests. In each test, one specifies a subset $S\subseteq [n]$ and learns whether $S$ contains one or more sick individuals.
By a counting argument, one gets a lower bound of $m = \Omega\bigl( \frac{k}{\log k}\log \frac{n}{k} \bigr)$ tests; however, the best known upper bound is $m = O( k\log \frac{n}{k} )$.
Question: Can one get rid of the $\log k$ factor in the lower bound; or, conversely, improve the upper bound to match it?
