Difference between revisions of "Open Problems:71"

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* '''Access:''' one can query at unit cost $d(x,y)$, for any $(x,y)\in S^2$
 
* '''Access:''' one can query at unit cost $d(x,y)$, for any $(x,y)\in S^2$
  
Czumaj and Sohler {{cite|CzumajS-09}} established that, on input $\varepsilon$, one can approximate the weight of the minimum spanning tree $\operatorname{weight}(\text{MST}(S))$ up to a multiplicative $(1+\varepsilon)$ in time $\tilde{O}(n\operatorname{poly}(\frac{1}{\varepsilon})$. In particular, this implies that it is possible to get a $(2+\varepsilon)$-approximation of $\operatorname{weight}(\text{TSP}(S))$ with the same time complexity.
+
Czumaj and Sohler {{cite|CzumajS-09}} established that, on input $\varepsilon$, one can approximate the weight of the minimum spanning tree $\operatorname{weight}(\text{MST}(S))$ up to a multiplicative $(1+\varepsilon)$ in time $\tilde{O}(n\operatorname{poly}(\frac{1}{\varepsilon}))$. In particular, this implies that it is possible to get a $(2+\varepsilon)$-approximation of $\operatorname{weight}(\text{TSP}(S))$ with the same time complexity.
  
 
'''Question:'''  can one beat this factor $2$ with only $o(n^2)$ queries? (And, even stronger, in $o(n^2)$ time?)
 
'''Question:'''  can one beat this factor $2$ with only $o(n^2)$ queries? (And, even stronger, in $o(n^2)$ time?)
  
 
'''Note:''' this is for arbitrary metrics. Under stronger assumptions, one can do better: for instance, it is known that a factor $\frac{7}{4}$ is achievable for $(1,2)$-metrics {{cite|???}}.
 
'''Note:''' this is for arbitrary metrics. Under stronger assumptions, one can do better: for instance, it is known that a factor $\frac{7}{4}$ is achievable for $(1,2)$-metrics {{cite|???}}.

Revision as of 02:50, 12 January 2016

Suggested by Krzysztof Onak
Source Baltimore 2016
Short link https://sublinear.info/71

Consider the following setting:

  • Input: a set $S$ of $n$ points from a metric space $(X,d)$
  • Access: one can query at unit cost $d(x,y)$, for any $(x,y)\in S^2$

Czumaj and Sohler [CzumajS-09] established that, on input $\varepsilon$, one can approximate the weight of the minimum spanning tree $\operatorname{weight}(\text{MST}(S))$ up to a multiplicative $(1+\varepsilon)$ in time $\tilde{O}(n\operatorname{poly}(\frac{1}{\varepsilon}))$. In particular, this implies that it is possible to get a $(2+\varepsilon)$-approximation of $\operatorname{weight}(\text{TSP}(S))$ with the same time complexity.

Question: can one beat this factor $2$ with only $o(n^2)$ queries? (And, even stronger, in $o(n^2)$ time?)

Note: this is for arbitrary metrics. Under stronger assumptions, one can do better: for instance, it is known that a factor $\frac{7}{4}$ is achievable for $(1,2)$-metrics [???].